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X^2+15X=27
We move all terms to the left:
X^2+15X-(27)=0
a = 1; b = 15; c = -27;
Δ = b2-4ac
Δ = 152-4·1·(-27)
Δ = 333
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{333}=\sqrt{9*37}=\sqrt{9}*\sqrt{37}=3\sqrt{37}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-3\sqrt{37}}{2*1}=\frac{-15-3\sqrt{37}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+3\sqrt{37}}{2*1}=\frac{-15+3\sqrt{37}}{2} $
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